## Friday, April 20, 2018

### How to Balance a Closed Traverse - Use of Compass(Bowditch) Rule - Solved Example

Hi,

Problem:
Following is the Field Data for a 4 sided, closed traverse, and you have to find the azimuth, bearings and corrected distances using Compass Rule or Bowditch Method.

Solution:
Download the image, solution is written for the angular closure, correction, azimuth, bearings, latitude and departure and corrected distance calculations.

## Thursday, April 19, 2018

### Derivation of Mass moment of Inertia for a Solid Cone

Hi,

Problem:
Derive the Mass Moment of Inertia of a solid cone with given mass density and angle half at vertex equal to 35 degrees. If the length of the cone is 5 m and mass density is 2.5 kg/m3, what is the mass moment of inertia.

Solution:

## Wednesday, April 18, 2018

### Complete Derivation of Mass Moment of Inertia of Hemisphere(Half Sphere) about the symmetric axis of Rotation.

Hi,

Problem:
The top half of the sphere is created by rotating the circle of x2+y2=r2 around the y-axis. If the rigid body has mass m and density (rho), find the mass moment of inertia about y-axis in terms of m and rho.

Solution:

## Monday, April 16, 2018

### How to Plot graph with Multiple Data Sets in Microsoft Excel (scatter function)

Hi,

If you have more than one data sets to be plotted on the graph, you can easily do that in excel under the 'insert'  scatter option. Follow the given eight steps with images.

Step.1 Make three data sets separately, and choose 'scatter' graph under 'insert' menu.

Step.2 Right click on the scatter graph, and select 'select data'

Step.3 Click on add and a small box will pop up. Give any series name, say 'Data Set 1', select all cells containing x -axis and y-axis values for the corresponding given boxes.Once you click 'ok' those blue data dots will appear on the scatter.

Step. 4 Now again click 'add' in the select data option, and then give another series name, say 'data set 2' and choose the corresponding data from data set 2 on the cells. Once done, those maroon colored dots will appear corresponding to 2nd data set.

Step. 5 Repeat step.4 for data set 3, and those light green dots will appear.
your 'select' data box will have now three series of data, and you can edit them or remove them, or you can even add another data set, by clicking on 'add'

Step.7 You can add trendlines to make it more appealing.
click on the series for which you want to add trendlines, once dots get selected, give a righ click, and this add trendline option will appear.

select among various options, how you want it to appear, linear, polynomial, etc. are various options, here I am selecting 'moving average.'

If you do same for all three series, this is how the final graph look like.

Thank you for vising!
Take care!

## Friday, April 13, 2018

### Use Method of Section on Gambrel Truss and Find section Forces - Solved Example

Hi,

Problem:
This is a Gambrel Truss with 5 known load forces on it as shown below. Let's say the reaction forces are already found, at A(0, 959.6 N) and at H(0, 450 N). Each applied load is 300 N.

Use the method of sections to determine all the unknown external forces acting on section ABG. Using your results, list whether members BD, BE, and EG are in compression or tension?

Solution:

Thank you for your kind visit.

### High Point of a Vertical Crest Curve - Solved Example

Hi,

Problem:
A 1200 ft crest vertical curve is defined by grades of +2.0 percent and -4.0 percent, respectively. If the elevation and station of the PVC is 200 ft and 202 + 30 respectively. determine the elevation and station of the highest point on the curve.

Solution:

Thank you for your kind visit. If you have any doubt, please let me know in the comment box.

## Thursday, April 12, 2018

### Increase in flow when Two parallel Identical Rectangular channels are combined to form Single with same Depth

Hi,

Problem: Two parallel identical rectangular channels have a base width B= 3ft and are flowing with a depth D= 2ft. Calculate the percentage increase in flow rate if the channels were combined into a single rectangular channel of bse width 2*B = 6 ft and the same channel depth.

Solution: